In the second part of unit 3, we began using much more of the different types of equations to find unknown variables such as acceleration, average velocity, etc. Using d=at^2/2 + VoT (nicknamed DAT) V=Vo +at (VAT) and V^2=Vo2 + 2ad (VAD) we learned how to plug in our data to solve for different problems such as the height of a cliff that takes 6 seconds to fall from. Given the variables a for acceleration (9.8m/s^2 or the force of gravity) t for time which was 6, and an initial velocity (Vo) of 0, we could plug in the numbers
d=(9.8m/s^2)(6sec^2)/2+0 where d (distance) would equal 176.4 meters.
we could also use this to find the velocity of when its about to hit the ground using
V^2 = 2(9.8m/s^2)(176.4m) where the velocity would be 58.8m/s.
once we learn how to factor in things such as air resistance, i feel like this lesson could very much be applied to everyday usage.
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